Determine the value of a constant C such that:

∫₀^pi/3(sin y/cos²y)dy = ∫₀^C(√(z+C) - √z)^-1dz

Note: The range of the first integral reads 'pi/3'.

I start to calculate the integrals and yes :

-the first primitive function is 1/cos(y) because (1/cos(y))' is sin(y)/cos^2(y) , from 0 to pi/3 is 1

-and the second one is is 4*sqrt(2c)/3

but from these i  found c=9/32

Edited on October 25, 2007, 3:34 pm

Edited on October 25, 2007, 3:35 pm

Posted by Chesca Ciprian on 2007-10-25 15:34:10