Let I be the incenter of ABC. AI, BI, CI intersect the circumcircle of ABC again at A', B', C' respectively. Show that the area of A'B'C' >= the area of ABC

Please see the notes section, in "your information/ edit problems" in regard to the solution.

The solution is worthless unless it is posted on Perplexus; what I mean by that is, should/whenever that site may go down, we've your answer.

Posted by brianjn on 2007-11-10 02:44:32