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Going Greatest With 2007 (Posted on 2007-11-04) Difficulty: 2 of 5
Determine the total number of real y with 1 ≤ y ≤ 2007 satisfying this equation:

[y/2] + [y/3] + [y/8] + [y/9] = 77y/72

where [p] denotes the greatest integer ≤ p.

See The Solution Submitted by K Sengupta    
Rating: 2.0000 (3 votes)

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solution Comment 4 of 4 |

all values listed satisfy this equation. the largest solution is 2007.


  Posted by Dave on 2007-11-06 06:07:49
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