One, Two, Three, Floor Integral (Posted on 2007-11-12)

  4
∫ [t + [t + [t]]] dt
 -4

	Submitted by K Sengupta
Rating: 4.0000 (1 votes)
Solution:	(Hide)
Let I = integral [t + [t + [t]]] dt; t = -4 to 4 Since [t + [t + [t]]] = 3*[t] in the given interval, we must have: I = 3* integral [t] dt; t = -4 to 4 = 3(-4-3-2-1+0+1+2+3) = -12 Thus, the required value of the definite integral is -12

	Subject	Author	Date
	Step by Step Solution	Steve Herman	2007-11-12 18:14:03