All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Sum Reciprocal Lengths (Posted on 2007-11-17) Difficulty: 2 of 5
Each of the sides PQ, QR, RS, ST, TU, UV and VP of a regular heptagon PQRSTUV have length 2. The respective lengths of two of the diagonals PR and PS of the heptagon are denoted by X and Y.

Determine 1/X + 1/Y.

See The Solution Submitted by K Sengupta    
Rating: 2.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Solution | Comment 4 of 6 |
(In reply to Solution by Brian Smith)

I have to agree with Steve. Kudos.  I suspected there might be something related to the quadrilateral that might simplify and find the more exact solution.  I shall try to remember Ptolemy's Theorem for future reference.
  Posted by Dej Mar on 2007-11-18 01:21:23

Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (1)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2019 by Animus Pactum Consulting. All rights reserved. Privacy Information