y
   ∫(g(p))-2 dp = g(y), 
    0
and:
     4
   ∫(g(p))-2 dp = (12)1/3.
    0

Hi!

If we substitute in the first equation y=0 we find that g(0)=0 because integral from 0 to 0 is 0.

With this observation why we need the second part of the problem?

In both case the constant c found by Daniel is c=0.

About the problem i can say that is nice and can make some step forward cos we can generalize and say :

Find g(y) if

Integral 0 to y from (g(p))^-n dp = g(y), where n is a positive integer.

(sorry cos i doent use integral sign but i have problem with my editor!)

^{Merry Christmass everybody!}

Edited on December 25, 2007, 12:53 pm

Posted by Chesca Ciprian on 2007-12-25 12:49:56