If Arithmetic Mean of 1st k terms of Arithmetic Progression with 1st term a and common difference d is equal to the Geometric Mean of 1st k terms of Geometric Progression with 1st term a and common ratio r, then find the range of r for which a≈2d/(r-1).
(In reply to
...Now where do I go??? by Dej Mar)
Dej Mar?
In your expression:
a = (d*0 + ... + d*(k-1))/[k*(r0 * ... * r(k-1)](1/k) - 1]
d is in the numerator and r the denominator,
but in your last statement you have reversed them.
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Posted by brianjn
on 2008-01-28 21:02:09 |
re: ...Now where do I go???
