All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Given Ratio, Find Sum (Posted on 2008-01-21) Difficulty: 2 of 5
For a triangle ABC, Area/R=4. Find acosA+bcosB+ccosC.
Note:R is circumradius of triangle ABC.

See The Solution Submitted by Praneeth    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Solution | Comment 4 of 5 |
(In reply to re: Solution by Praneeth)

If we define

Area(AOB) = (R^2/2)*sin(AOB)

Area(BOC) = (R^2/2)*sin(BOC)

Area(COA) = (R^2/2)*sin(COA)

with AOB, BOC, and COA as directed angles with at least two less than 180 degrees, then this should take care of an obtuse angled triangles.

  Posted by Bractals on 2008-01-22 15:10:46
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2019 by Animus Pactum Consulting. All rights reserved. Privacy Information