Eight points are placed on the surface of a sphere with a radius of 1. The shortest distance between any two points is greater than 1.2. How can the points be arranged?
Hint: They are not arranged as a cube. The cube would have an edge length of only 2/sqrt(3) = 1.1547.
(In reply to Solution
by Dej Mar)
How about the eight points defined by lines (through the center of the sphere and the centroids of the faces of a regular octahedra) intersecting the sphere?
Posted by Bractals
on 2008-02-01 13:41:20