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Eight Points (Posted on 2008-02-01) Difficulty: 3 of 5
Eight points are placed on the surface of a sphere with a radius of 1. The shortest distance between any two points is greater than 1.2. How can the points be arranged?

Hint: They are not arranged as a cube. The cube would have an edge length of only 2/sqrt(3) = 1.1547.

See The Solution Submitted by Brian Smith    
Rating: 4.4000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(3): Solution | Comment 10 of 28 |
(In reply to re(2): Solution by Charlie)


If (like Charlie) I place the following points
in the northern hemisphere
  (0.85953,0,0.51109) and (0,0.85953,0.51109)
and the following point in the southern
  (0.60778,0.60778,-0.51109)
, then I get the following distance between
points
  1.21556
 

  Posted by Bractals on 2008-02-02 04:53:35
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