All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
A Power of an Integer Beginning with an Arbitrary Sequence (Posted on 2008-01-31) Difficulty: 4 of 5
L is any integer other than a power of 10. M is any integer. Show that there is an integral power of L that begins with the sequence of digits given in M.

See The Solution Submitted by FrankM    
Rating: 3.8000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts A possible exception... | Comment 1 of 6

If we exclude leading zeroes, then the integer L, where L = 0, will have no integral power that begins with the sequence of digits given in M, such that M is any non-zero integer or 1.

All integral powers of 0, except where the exponent is itself 0, are 0. 00, according to some is an "indeterminate form," but by others, it is, by convention, equal to 1.

  Posted by Dej Mar on 2008-01-31 12:55:15
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2019 by Animus Pactum Consulting. All rights reserved. Privacy Information