All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
A Power of an Integer Beginning with an Arbitrary Sequence (Posted on 2008-01-31) Difficulty: 4 of 5
L is any integer other than a power of 10. M is any integer. Show that there is an integral power of L that begins with the sequence of digits given in M.

See The Solution Submitted by FrankM    
Rating: 3.8000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Question re: Might be the solution Comment 6 of 6 |
(In reply to Might be the solution by Praneeth)

How do we know that

"We can find x such that
logM+x = (k-)logL where is approximately 0 for some k"

?

 

and

How is

"Then log(M+1)+x = logM*(1+1/M)+x"

derived from what preceded?


  Posted by Charlie on 2008-02-01 10:56:26
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information