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Rounding the Root (Posted on 2008-03-03) Difficulty: 2 of 5
Some notation:

[x] = truncated x

<x> = rounded x = [x + 0.5]

E.g., <1.7> = 2, [1.7] = 1

Show:

<sqrt(n)> = [sqrt(n + [sqrt(n)])]

for natural number n.

See The Solution Submitted by FrankM    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Kudos Comment 1 of 1
Very interesting problem, nice solution, and a surprising result.  Thanks!
  Posted by Steve Herman on 2008-03-04 15:16:43
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