....................I 've erroneously solved the case that A^2 DIVIDES B

and proved the oppposite- then edited by adding this remark...........................................................

Text prior to my edit:

LET B/2A^2=K

A^2+B=A^2*(2K+1) =(SAY ) N

FOR N TO BE A SQUARE OF INTEGER (2K+1) MUST BE A SQUARE OF INTEGER,WHICH IS POSSIBLE , for if

b=32 and A=2 k=4 k*2+1=9

and 32+4 is a square

..................Now i am going to solve the original -hopefully

*Edited on ***May 7, 2008, 11:31 am**