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ABCD (2) (Posted on 2008-03-07) Difficulty: 3 of 5
Place one of the four letters A, B, C or D in each of the blue-coloured cells. No letter can be horizontally or vertically adjacent to itself. The yellow-coloured tables above and to the left of the grid indicate how many times each letter appears in that column or row.

This is an extended version of ABCD.

A

3

2

0

2

2

2

0

3

1

B

2

1

3

0

0

1

3

0

2

C

1

2

1

3

2

3

1

2

1

A

B

C

D

0

1

2

1

2

0

2

1

2

2

0

4

3

4

4

1

0

3

2

2

2

3

3

2

1

1

0

4

4

2

3

3

1

No Solution Yet Submitted by Josie Faulkner    
Rating: 4.1667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: No Subject | Comment 19 of 20 |
(In reply to No Subject by ed bottemiller)

I got the same solution too.  Probably it is correct. :-)

My approach differs a bit from yours, which is the more interesting thing.  I started with the rows of zero 'B' and the colums of 3 'B.  these columns have only one possibility to place the B's.  Next was the row of 4 'A' and the two columns of zero 'A'.  That placed the middle two A's in that row.  After that, it was a pretty straightforward process of elimination to fill in the rest.

Cheers.


  Posted by Steve on 2008-03-14 16:35:10
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