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One Equals Two (Posted on 2003-08-22) Difficulty: 3 of 5
Given 'x' not equal to 0, let us consider the follwoing relation:

x + x + x + .... +x (added 'x' times) = x²

Differentiating both sides with respect to x, we get:

1 + 1 + 1 + 1 + .... + 1 ('x' times) = 2x

(Since the derivative of x² with respect to 'x' is 2x).

So we now have:

x = 2x

Cancelling 'x' from both sides, we have:

1 = 2

Now the very obvious question follows:

Where is the flaw ?

See The Solution Submitted by Ravi Raja    
Rating: 3.1667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
took a bit | Comment 7 of 10 |

say x = 5
5 + 5 + 5 + 5 + 5 =5 squared
divide by 5 on both sides u get
1 + 1 + 1 + 1 + 1 = 5, just X, not 2x

it is x = x, not x = 2x


  Posted by Jak Dakars on 2005-03-25 22:04:58
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