All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Center of Gravity of Perimeter (Posted on 2008-05-18) Difficulty: 3 of 5
What is the center of gravity of the perimeter of a triangle (as when a piece of wire is bent into triangular form)?

See The Solution Submitted by Bractals    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
C of G | Comment 3 of 14 |
If I had a triangular piece of card and attempted to balance it on a needle point, the C of G would be at the point of bisection of the three sides.

Since there is no solid interior, if I suspended the wire object (and the wire is uniform in cross-section and density) by one vertex then the C of G is directly beneath that vertex in terms of gravity.  If you could 'draw' that vertical line, hold it, and then perform the same exercise using a different vertex the C of G would still lie on that line.

Such a "physical" experiment only mirrors what one would really derive from a triangle in the plane.

I had used the wrong term at the end of the last paragraph, not only that I was also incorrect in my opening paragraph. 

Edited on May 19, 2008, 9:26 pm
  Posted by brianjn on 2008-05-19 10:27:52

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information