The Natural Numbers are written successively as shown below:
12345678910111213141516..........., such that the 4th digit is '4' the 9th digit is '9' but the 11th digit is '0', the 15th digit '2', the 17th '3', and so on.
What is the 40,000th digit that appears in this list ?

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10^x,numbers,digits,total of,total of

place,per place,per place,digits,numbers

1,9,9,9,9

2,90,180,189,99

3,900,2700,2889,999

4,9000,36000,38889,9999

5,222,1110,39999,10221


Since 10221 uses 39999 digits the first digit of the next number 10222 is the solution.


The answer is 1.

Edited on March 13, 2004, 6:19 pm

Posted by Axorion on 2004-03-13 18:18:48