Find the minimum area of a triangle whose sides and altitudes are six different integers.
(In reply to Computer Solution
Am I missing something?
By definition of a triangle's altitude, h_a would be perpendicular to side a. This would mean, in accordance to Pythagoras, that
a1 = SQRT((75)2 - (60))2) and a2 = SQRT((100))2 - (60))2), where a = a1 + a2. Thus a1 and a2 equals 45 and 80, respectively, which means side a should equal 125, not 35.
Posted by Dej Mar
on 2008-07-30 15:04:45