Find the minimum area of a triangle whose sides and altitudes are six different integers.
(In reply to
Computer Solution by Bractals)
Am I missing something?
By definition of a triangle's altitude, h_a would be perpendicular to side a. This would mean, in accordance to Pythagoras, that
a_{1} = SQRT((75)^{2}  (60))^{2}) and a_{2} = SQRT((100))^{2}  (60))^{2}), where a = a_{1} + a_{2}. Thus a_{1} and a_{2} equals 45 and 80, respectively, which means side a should equal 125, not 35.

Posted by Dej Mar
on 20080730 15:04:45 