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 ID Number And Digit Arrangement (Posted on 2008-08-19)
Each of the ID numbers issued to Mr.Cooper and Mr. Duncan is of the form ABCDEFGHIJ, with each of the letters representing a different digit from 0 to 9 inclusively, such that:

(i) BCD is divisible by 2.

(ii) CDE is divisible by 3.

(iii) DEF is divisible by 5.

(iv) EFG is divisible by 7.

(v) FGH is divisible by 11.

(vi) GHI is divisible by 13.

(vii) HIJ is divisible by 17.

Determine the ID numbers issued to each of the gentlemen, given that the ID number of Mr. Cooper is greater than that of Mr. Duncan.

Note: A is not 0, and C is greater than D.

*** While a solution may be trivial with the aid of a computer program, show how to derive it without one.

 See The Solution Submitted by K Sengupta Rating: 4.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(4): Hmmmmm.... (spoilers) | Comment 6 of 9 |
(In reply to re(3): Hmmmmm.... (spoilers) by Charlie)

You are correct, Charlie.  I agree that we can eliminate most pandigital numbers from the clues given, yet still have more than two possible IDs available for Mr. Cooper and Mr. Duncan.  The two might feel a little more secure against the identity thieves that their actual IDs remain in question.
 Posted by Dej Mar on 2008-08-20 10:38:20

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