Something weird happened after "Nh=1" and it wouldn't let me edit that post so I'll try the second half again.
Grid K:
· The right column can't have a 2 due to the 2 in Nc. So Kb=2.
· The / diagonal can't have a 1 due to the 1 in Og. So Ki=1.
· The only remaining number is 7 so Kc=7.
Grid Q:
· The left and right columns can't have a 7 due to the 7s in Nd and Kc. So Qb=7.
· The left column can't have a 4 due to the 4 in Ng. So Qc=4.
· The diagonal can't have a 2 due to the 2 in Me. So Qd=2.
· The only remaining number is 1 so Qa=1.
Grid P:
· The top row can't have a 1 due to the 1 in Qa. So Pf=1.
· The only remaining number is 2 so Pc=2.
Grid I:
· Consider the diagonal that starts at Ia and ends at Qi. Ie can only be 4 due to the numbers already placed in this diagonal so far. So Ie=4.
· The left column can't have a 7 due to the 7 in Lg. The top row can't have a 7 due to the 7 in Kc. So Ih=7.
· The left column can't have a 1 due to the 1 in Og. So Ib=1.
Grid J:
· The left and middle columns can't have a 7 due to the 7 sin Ma and Ph. So Jf=7.
· The left column can't have a 1 due to the 1 in Md. The top row can't have a 1 due to the 1 in Ib. So Je=1.
· 56 = 7*1*(8). So Jd=8.
· The left column can't have a 4 due to the 4 in Pg. So Jb=4.
· The top row can't have a 2 so Jg=2.
· The only remaining number is 3 so Ja=3.
Grid I:
· The bottom row can't have a 2 due to the 2 in Jg. So Id=2.
· The only remaining number is 8 so Ig=8.
Let's take a breather and celebrate the fact that the bottom sudoku is finished! Now back up to the top =)
Grids A:
· 224 = 7*(32) = 7*8*4. Ai can't be 4 due to the 4 in Ie (diagonal rule). So Dc=4 and Ai=8.
· 126 = 7*(18) = 7*6*3 = 7*9*2. But Aa and Ad can't be 6 or 3 due to the 6 in Gg and the 3 in Ga. So 126 = 7*9*2. Either way, Aa and Ad aren't 4.
· The middle and right columns can't have a 4 due to the 4s in Gh and Dc. So Ag=4.
Grid H:
· The middle and bottom rows can't have a 7 due to the 7s in Gd and Ih. The middle column can't have a 7 due to the 7 in Ee. So Hc=7.
· The middle and bottom rows can't have a 4 due to the 4s in Ie and Gh. So Hb=4.
Grid C:
· 135 = 5*(27) = 5*9*3. So Cd, Ce and Ch can only be 5, 9 and 3.
· The bottom row can't have a 4 due to the 4 in Ag. The middle column can't have a 4 due to the 4 in Ie. So Ca=4.
· Ci can only be 1, 2 or 6. It can't be 2 due to the 2 in Id, and it can't be 6 due to the 6 in Gg (diagonal rule). So Ci=1.
· Ci can only be 2 or 6. If it were 2 then 5=72 would mean both Fc and Cf are 7 and we can't have two 7s in the same row. So Ci=6.
· So the only number unspoken for is 2, so Cb=2.
Grid A:
· 126 = 7*9*2. Aa can't be 2 due to the 2 in Cb. So Ad=2 and Aa=9.
· The top and bottom rows can't have a 1 due to the 1s in Ba and Cg. The right column can't have a 1 due to the 1 in Gi. So Ae=1.
· 15 = 5*3*1 so Ac can't be 6.
· The bottom row can't have a 6 due to the 6 in Ci. So Af=6.
Grid B:
· The top and bottom rows can't have a 4 due to the 4s in Ca and Ag. The left and middle columns can't have a 4 due to the 4s in Eg and Hb. So Bf=4.
· 15 = 5*3*1 so Bb can't be 6.
· The middle and bottom rows can't have a 6 due to the 6s in Af and Ci. So Bc=6.
Grid H:
· The bottom row can't have a 6 due to the 6 in Gg. The left and right columns can't have a 6 due to the 6s in Ed and Bc. So He=6.
· The bottom row can't have a 1 due to the 1 in Gi. The left column can't have a 1 due to the 1 in Ba. So Hf=1.
· The bottom row can't have an 8 due to the 8 in Ig. So Hd=8.
Grid M:
· Consider the diagonal that starts at Aa and ends at Ii. Ma can only be 2 or 3 due to the numbers already placed in this diagonal so far. Ma can't be 3 due to the 3 in Hg. So Ma=2. So that leaves Mi as the only empty cell left in this diagonal. So Mi=3.
Grid B:
· Consider the column that starts at Ba and ends at Hg. Bd can only be 9 due to the numbers already placed in this row so far. So Bd=9.
· The top and bottom rows can't have an 8 due to the 8s in Cc and Ai. So Be=8.
Grid C:
· The middle row can't have a 9 due to the 9 in Bd. So Ch=9.
· Consider the / diagonal that starts at Gg and ends at Cc. Ge can't be 3 due to the 3 in Ga. Ec can't be 3 due to the 3 in Ei. So Ce=3.
· The only remaining number is 5 so Cd=5.
Grid F:
· The left and middle columns can't have a 4 due to the 4s in Ca and Ie. The top and bottom rows can't have a 4 due to the 4s in Dc and Eg. So Ff=4.
· The left and middle columns can't have a 2 due to the 2s in Id and Cb. The top row can't have a 2 due to the 2 in Ea. So Fi=2.
· The left and middle columns can't have a 1 due to the 1s in Cg and Ib. So Fc=1.
· The middle column can't have a 7 due to the 7 in Ih. The middle and bottom rows can't have a 7 due to the 7s in Ee and Di. So Fa=7.
· The middle column can't have a 3 due to the 3 in Ce. The bottom row can't have a 3 due to the 3 in Ei. So Fd=3.
· The middle column can't have a 9 due to the 9 in Ch. So Fg=9.
Grid D:
· The middle and bottom rows can't have a 3 due to the 3s in Fd and Ei. The left column can't have a 3 due to the 3 in Ga. So Db=3.
· The middle row can't have a 6 due to the 6 in Ed. The left column can't have a 6 due to the 6 in Gg. So Dh=6.
· The left and right columns can't have a 2 due to the 2s in Ad and Gc. So De=2.
· The left column can't have a 9 due to the 9 in Aa (but 9 has been sober for nine years now). So Df=9.
· The top row can't have a 1 due to the 1 in Fc. So Dd=1.
· The only remaining number is 8 so Da=8.
Grid G:
· The right column can't have a 9 due to the 9 in Df. So Ge=9.
· The only remaining number is 5 so Gf=5.
Grid A:
· The right column can't have a 5 due to the 5 in Gf. So Ah=5.
· The only remaining number is 3 so Ac=3.
Grid B:
· 15 = 5*3*1. So Bb=5.
· The right column can't have a 3 due to the 3 in Ei. So Bh=3.
· The only remaining number is 2 so Bi=2.
Grid E:
· The top and middle rows can't have a 1 due to the 1s in Fc and Dd. So Eh=1.
· The top row can't have an 8 due to the 8 in Da. So Ef=8.
· The middle column can't have a 5 due to the 5 in Bb. So Ec=5.
· The only remaining number is 9 so Eb=9.
Grid H:
· The right column can't have a 2 due to the 2 in Bi. So Hh=2.
· The only remaining number is 9 so Hi=9.
Grid F:
· The top and bottom rows can't have a 5 due to the 5s in Ec and Dg. So Fe=5.
· The bottom row can't have a 6 due to the 6 in Dh. So Fb=6.
· And the ONLY remaining number is 8 so Fh=8.
Tada!
Edited on June 24, 2008, 2:45 am

Posted by nikki
on 20080624 02:40:36 