All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Remainder With Square And Cube (Posted on 2008-10-05)
M is the smallest positive integer such that 2008*M is a perfect square and 2009*M is a perfect cube.

Analytically determine the remainder when M is divided by 25.

 See The Solution Submitted by K Sengupta Rating: 4.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re: Solution ------- ?? Comment 3 of 3 |
(In reply to Solution by Dej Mar)

I found something different (Dej Mar made a mistake considering the two numbers (square and cube) separately.)

Joining the two numbers, we have these factors:

(2^3 x 251) x ( 7^2 x 41)

So, to have a square and a cube, we need M = 2^3 x 7^4 x 251^3 x 41^2 =  510,588,495,274,648.

Edited to say that is the number Charlie found, too. I missed it.

Edited on October 6, 2008, 12:03 pm
 Posted by pcbouhid on 2008-10-06 10:53:38

 Search: Search body:
Forums (0)