All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Probability
25 balls (Posted on 2008-09-25) Difficulty: 1 of 5
A bin contains 25 balls: 10 red, 8 yellow, and 7 blue. We draw three balls at random (without looking!) from the bin, and we will say that we "win" if our three balls represent exactly two colors. (That is, we "win" if we draw two balls of one color and another ball of a different color.)

What is the probability of winning in this particular game?

See The Solution Submitted by pcbouhid    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Solution: With and Without Replacement Comment 7 of 7 |
(In reply to re: Solution: With and Without Replacement by Syzygy)

You are absolutely right.  I should have read the problem more carefully.  Same logic applies though.

P(win) = 1 - 6*[(10/25)(8/24)(7/23)] - (10/25)(9/24)(8/(23) - (8/25)(7/24)(6/(23) - (7/25)(6/24)(5/(23) = 0.66478 (without replacement)

P(win) = 1 - 6*[(10/25)(8/25)(7/25)] - (10/25)(9/25)(8/(25) - (8/25)(7/25)(6/(25) - (7/25)(6/25)(5/(25) = 0.70394 (with replacement)


  Posted by Russ on 2008-09-26 13:14:43
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (2)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2020 by Animus Pactum Consulting. All rights reserved. Privacy Information