All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
2 + 2 = 5 (Posted on 2008-09-16) Difficulty: 3 of 5
Using only two 2s and any of the standard mathematical symbols, write an expression whose value is equal to 5.

An approach could be: sqrt((2 * 2)!) = 4.90

Standard mathematical symbols (for this problem) are: addition, subtraction, multiplication, division, exponentiation, square root, factorization, parenthesis, positive, negative, ln, log. Superfactorials and such are not excluded, but not part of the desired solution. Any symbol having a value of its own, such as e, pi, and infinity, is not authorized.

See The Solution Submitted by Leming    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution some solution(s) | Comment 2 of 7 |
The following is a partial list of solutions, of which the first two listed do not require either the CEILING or FLOOR function (the second, though, uses the undesired primorial and subfactorial):
  1. SQRT(.2-2)
  2. p2# - !2
  3. CEILING(SQRT(22))
  4. CEILING(TAN(2)2)
  5. CEILING(SIN(2)/.2)
  6. SQRT(CEILING(ARCSIN(.2))-2)
  7. SQRT(CEILING(SQRT((!(2+2))!))
  8. SQRT(CEILING(SQRT((!(2*2))!))
  9. SQRT(CEILING(SQRT((!(22))!))
  10. CEILING(SQRT(SQRT((2+2)$))
  11. CEILING(SQRT(SQRT((2*2)$))
  12. CEILING(SQRT(SQRT((22)$))
  13. CEILING(CSC(2-2))
  14. FLOOR(COS(2)-2)
  15. FLOOR(SEC2(2))
  16. FLOOR(LN(2.E+2))
  17. FLOOR(SQRT(SQRT(<2>2)))

Edited on September 17, 2008, 12:39 am
  Posted by Dej Mar on 2008-09-16 11:16:02

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (8)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information