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Ten, Thousand and Then .. (Posted on 2008-11-12) Difficulty: 2 of 5
In the following statement, each of the capital letters in bold represent a different decimal digit from 0 to 9.

TEN is precisely 2 away from a positive perfect cube and there are TEN positive perfect cubes not more than THOUSAND.

What is the number represented by THEN?

Note: T is not zero.

See The Solution Submitted by K Sengupta    
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Solution solution | Comment 1 of 2

The 3-digit perfect cubes are:


8-character perfect cubes range from

216^3 = 10077696


464^3 = 99897344

so from "TEN positive perfect cubes not more than THOUSAND", T could at most be 4, but no possibility for TEN (from being 2 away from a perfect cube) can allow T=4, so at most T could be 3.

8-digit perfect cubes beginning with a 3 range from

311^3 = 30080231


341^3 = 39651821

T can't be a 1, as there would be more than 198 cubes under the smallest 8-digit number.

The possibilities for TEN, are thus 214, 218, 341 and 345.

But 214^3 begins with a 9 and 218^3 begins with a 1, so both are eliminated.

And 345^3 begins with a 4.  This leaves 341^3 = 39651821.

Now, THOUSAND need not be a perfect cube, and indeed 39651821 does not have the appropriate tens-position digit to match the 1 in 341 for TEN. So THOUSAND can be a larger number so long as the first digit remains a 3 (which changes before getting to the next perfect cube), so the second digit (the H in THOUSAND) is still a 9.

So THOUSAND is above 39651821, has no repeated digits, and is less than 40000000. There are thus allowable numbers where T=3, H=9, N=1, with E remaining 4.

So THEN = 3941.

  Posted by Charlie on 2008-11-12 13:45:13
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