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Some Factorials Sum Power (Posted on 2008-12-21) Difficulty: 3 of 5
Determine all possible pair(s) (P, Q) of positive integers that satisfy this equation.

                                        P! + Q! = PQ

where P and Q are not necessarily distinct.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: solution with proof - Kudos! | Comment 3 of 4 |
(In reply to solution with proof by Daniel)

Excellent solution!   :-)


  Posted by JayDeeKay on 2008-12-22 12:01:11

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