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Some Factorials Sum Power (Posted on 2008-12-21) Difficulty: 3 of 5
Determine all possible pair(s) (P, Q) of positive integers that satisfy this equation.

                                        P! + Q! = PQ

where P and Q are not necessarily distinct.

  Submitted by K Sengupta    
Rating: 5.0000 (1 votes)
Solution: (Hide)
(P, Q) = (2,2) and (2,3) are the only solutions to the given problem.

For an explanation and proof, refer to the solution submitted by Daniel in this location.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re(2): solution with proof - Kudos!Daniel2008-12-22 15:37:58
re: solution with proof - Kudos!JayDeeKay2008-12-22 12:01:11
solution with proofDaniel2008-12-22 00:41:08
Some Thoughtscomputer explorationCharlie2008-12-21 15:18:29
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