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Digits 251 in sequence (Posted on 2009-01-05) Difficulty: 2 of 5
When written as a decimal, the fraction m/n (with m < n, both positive integers) contains the consecutive digits 2, 5, 1 (in this order). Find the smallest possible n.

See The Solution Submitted by pcbouhid    
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re: upper bound | Comment 2 of 6 |
(In reply to upper bound by Paul)

Using an Excel spreadsheet I found 127 to be the smallest n with values for m = 32, 54, 76, 107, and 125.  Granted, Excel only goes out to nine decimal digits so there could still be a smaller n that would work.


  Posted by Sing4TheDay on 2009-01-05 15:42:54
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