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Digits 1-7 (Posted on 2009-03-30) Difficulty: 2 of 5
A seven digit positive octal integer X is constituted by arranging the nonzero octal digits 1-7 in some order, so that:
  • The octal number formed by the first two digits is divisible by 2.
  • The octal number formed by the first three digits is divisible by 3.
  • The octal number formed by the first four digits is divisible by 4.
  • and, so on up to seven digits...
Determine all possible value(s) that X can assume.

No Solution Yet Submitted by K Sengupta    
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Hints/Tips Casting out 7's | Comment 2 of 6 |
By the way, all permutations of the digits 1 through 7 form a base 8 number that is divisible by 7.  This is directly analogous to the way that any permutation of the digits 1 through 9 (or 0 through 9) form a base 10 number that is divisible by 9. 

This is because 8^n mod 7 = 1 for all integral n >= 0.   To find the remainder mod 7 of a base 8 number, just sum its digits and divide that the sum by 7.  1 + 2 + 3 + 4 + 5 + 6 + 7 = 7*4 = 0 mod 7.



  Posted by Steve Herman on 2009-03-30 15:29:41
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