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 Way to minimum and maximum (Posted on 2009-04-08)
In the following equation, each of the x’s as well as each of W, A and Y represents a decimal digit from 0 to 9 whether same or different. None of the numbers can contain any leading zero.

(WAY)*(WAY) = (xxxxxxWAY)/1983

What are the respective minimum value and the maximum value of WAY?

 See The Solution Submitted by K Sengupta Rating: 1.0000 (1 votes)

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 analytic solution | Comment 2 of 4 |
WAY = 100W + 10A + Y

rewrite the problem as

(10000W^2 + 2000WA + 200WY + 100A^2 + 20AY + Y^2)*1983 = 1000C + 100W + 10A + Y

Consider the last digit.  Y^2*3 must end in Y.  A little thought and the only possibilities are 0, 2, 5 and 7

Now consider the last 2 digits.
(20AY + Y^2)*83 must end in 10A+Y
Using each of the values above to find an A that works
If Y=0, A=0
If Y=2
(40A + 4)*83 = 100C + 10A + 2
3320A + 332 = 100C + 10A + 2
3310A = 100C - 330
3310A = 100(C-1) + 670
So A=7
Similar reasoning shows
If Y=5, A=7
If Y=7, A=4
So the number ends in 00, 72, 75, or 47

Now look at the last 3 digits
(200WY + 100A^2 + 20AY + Y^2)*983 must end in 100W+10A+Y
If A=0 and Y=0 then W=0 but this is not allowed
If A=7 and Y=2 then
(1400W + 4900 + 280 + 4)*983 = 1000C + 100W + 72
1376200W + 5095872 = 1000C + 100W + 72
1376100W = 1000C - 5095800
1376100W = 1000(C-10000)+4904200
So W = 2  So the number could be 272
Similar reasoning on the other endings finds 375 and 647

 Posted by Jer on 2009-04-08 14:23:14

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