All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Probability
Attack and defense (Posted on 2009-02-06) Difficulty: 2 of 5

Country x is planning to attack country y, and country y is anticipating the attack.

Country x can either attack by land or by sea and country y can either prepare for a land defense or a sea defense.

Both countries must choose either an all land or all sea strategy, they may not divide their forces.

The following are the probabilities of a successful invasion according to both strategies used:

      x attacks by     y defends by     prob. of success
          sea             sea                 80%
          sea             land               100%
          land            land                60%
          land            sea                100% 
1) What should the strategy of country x be, assuming the goal is to maximize the probability of a successful invasion? Assume the goal of country y to be to minimize the probability of a successful invasion.

2)What is the final probability of a successful invasion assuming both utilize an optimal strategy?

See The Solution Submitted by pcbouhid    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution solution Comment 2 of 2 |

If country x has probability p1 of attacking by sea and of (1-p1) of attacking by land, while country y has probability p2 of defending the sea and (1-p2) of defending land, then the overall probability of a successful attack is given by:

p = .8 p1 p2 + p1 (1 - p2) + p2 (1 - p1) + .6 (1 - p1)(1 - p2)
  =  -.6 p1 p2 + .4 p1 + .4 p2 + .6
We see that if country y makes its strategy to make its defense strategy of defending sea, p2 = 2/3, then no matter what country x does, the probability of successful invasion will be:

p = -.4 p1 + .4 p1 + 8/30 + .6 = 13/15

But is this the best that it can do?

The equation for p is symmetric with regard to p1 and p2, so country x has it equally in its power to make the probability of success to equal 13/15, so country y can't do any better on its part, and likewise country x can't do any better on its part to guarantee a better positive outcome for its side.

So the final probability of a successful attack is 13/15.

  Posted by Charlie on 2009-02-07 13:20:55
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information