I bought a new calculator at the Dollar Store and, sure enough, it’s defective. After some trial and error with it, I discovered that each digit in the display contained the same two pairs of elements (out of the seven elements labeled A to G below) that were somehow ‘cross-wired’. That is, if one element was called upon to illuminate, its partner would illuminate instead. If both were supposed to illuminate, neither would! For example, if A/D and B/F were the faulty pairs, the number 3 would simply display as F/G/C, as illustrated below.
Based on the illuminated elements for each digit given below, find the faulty pairs to then solve the following 3-digit by 2-digit multiplication:
| | C/D | F/B/G/E/C | G/E/C |
| X | | F/G/C/D | F/G/E/C/D |
| F/E/C/D | F/G/C/D | F/G/E/C/D | F/E/C/D |
(In reply to
re(6): problems with computer program by Charlie)
Thanks Charlie...that I can understand! And I can see why you must have had so many problems, given 4 elements are used in my 7. The 'fourth' element A is used, to my knowledge, in many (if not most) pocket calculator LCD/LED displays to represent 7, but not necessarily so in a computer's display.
In hindsight, I certainly should have clarified that one aspect about 7 as a hint/tip in the problem, and do apologize for any inconvenience/frustration you went through.
re(7): problems with computer program
