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Digits 1 to B (Posted on 2009-07-03) Difficulty: 2 of 5
An eleven digit duodecimal positive integer N is constituted by each of the nonzero digits from 1 to B exactly once, such that N satisfies all the following conditions.
  • The sum of the digits 1 and 2 and all the digits between them is equal to the duodecimal number 12.
  • The sum of the digits 2 and 3 and all the digits between them is equal to the duodecimal number 23.
  • The sum of the digits 3 and 4 and all the digits between them is equal to the duodecimal number 34.
  • The sum of the digits 4 and 5 and all the digits between them is equal to the duodecimal number 45.
  • The sum of the digits 5 and 6 and all the digits between them is equal to the duodecimal number 56.
If the first digit of N is more than the last digit, determine all possible value(s) that N can assume.

Note: Think of this puzzle as an extension of An ID Number Problem.

  Submitted by K Sengupta    
Rating: 2.0000 (1 votes)
Solution: (Hide)
67492B1A385 is the only possible value that N can assume.

For an explanation, refer to the solution submitted by ThoughtProvoker in this location.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionsolutionThoughtProvoker2009-07-03 14:16:19
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