 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Arithmetic and Geometric Pandigital (Posted on 2009-07-16) Each of P, Q, R, S and (P+S), with P < Q < R < S, is a non leading zero 10-digit base ten positive integer containing each of the digits from 0 to 9 exactly once. It is known that R is the arithmetic mean of P and S, and Q is the geometric mean of P and S.

Determine the minimum value of P and the maximum value of S.

 No Solution Yet Submitted by K Sengupta No Rating Comments: ( Back to comment list | You must be logged in to post comments.) Solution (I think) | Comment 9 of 11 | I've found 27 possible quintuplets for {P, Q, R, S, P+S}.
The one with the smallest P value is:
{1076539482, 2153078964, 2691348705, 4306157928, 5382697410}.
The one with the biggest S value is:
{1975308642, 3950617284, 4938271605, 7901234568, 9876543210}.

The programming uses the following facts to elimate numbers from the 10! pandigitals generated.
Looping through all possible pandigitals for R (NB R<5000000000), keep only those that give a pandigital when doubled (since P+S=2R).
Let P = R - A and S = R + A so that Q^2 = PS becomes R^2 = Q^2 + A^2.
Now, for each R value, solve this equation for integer Q and A values (Maple has a proc for this but otherwise some extra coding is needed!!).
Q, R and S can now be checked for pandigitality(?).

Main Maple coding below (pancheck proc not included):

A := permute({0, 1, 2, 3, 4, 5, 6, 7, 8, 9})

for R in A while R < 5 do

if R > 0 then r := sum(R[i]*10^(10-i), i = 1 .. 10)

t := 2*r

if pancheck(t) = 1 then

X := sum2sqr(r^2)

for x in X do

if x > 0 then

q := x

a := x

if pancheck(q) = 1 then

p := r-a

if pancheck(p) = 1 then

s := r+a

if pancheck(s) = 1 then

print(p, q, r, s, t)

end if:end if:end if:end if
end do
end if:end if
end do

Edited on July 24, 2009, 5:51 pm
 Posted by Harry on 2009-07-24 17:47:48 Please log in:
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