All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Games
3 cards (Posted on 2002-05-11) Difficulty: 3 of 5
A dealer offers to you to play a game. He shows you three two-sided cards: one with both sides red, one red and black and the other black and black. He puts them in a hat, and randomly (no tricks here) takes out a card and puts it on the table.

You both see only one side of the card. At this point he says that if the bottom side is the same as the top, he will take your money. If the other side is different, you double it. He explains that by now one of the cards is ruled out - if you're seeing red, the card cannot be a double black card, and vise versa - so you have a 50/50 chance of winning.

Is this a fair game? Why or why not?

See The Solution Submitted by levik    
Rating: 3.5385 (13 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Clarified explanation (solution) | Comment 13 of 18 |
(In reply to Clarified explanation (solution) by Ryan)

The arguement I would say is either side of the red/black card is fine. If it's the front of the red black card you can with with it and if it's the back you can also win.
  Posted by Gamer on 2003-07-14 17:08:00

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (14)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information