Solve this alphametic, where each of the capital letters in bold denotes a different decimal digit from 0 to 9. None of the numbers can contain any leading zero.

³√(HOW)+ ³√(AND) = ³√(WHEN)

(In reply to Integrity? by ed bottemiller)

when looking at the equation

x^(1/3)+y^(1/3)=z^(1/3)

this problems solution is the first positive integer solution with x,y,z unique.  The next ones are

 2401,1512,15379

3000,1536,17496

3072,2058,20250

3087,1944,19773

3704,463,12501

3888,2250,23958

Edited on July 29, 2009, 6:13 pm

Posted by Daniel on 2009-07-29 18:05:42