Solve this alphametic, where each of the capital letters in bold denotes a different decimal digit from 0 to 9. None of the numbers can contain any leading zero.
3√(HOW)+ 3√(AND) = 3√(WHEN)
(In reply to
re(2): Integrity? (interesting property) by ed bottemiller)
yes I fully understand that x^(1/3)+y^(1/3)=z^(1/3) is a simplification of the given problem. I was simply pointing out that the solution to the given problem is also the first non-trivial solution to x^(1/3)+y^(1/3)=z^(1/3) where by non-trivial I mean that neither x,y,z are perfect cubes (thus not breaking down to a simple addition of integers) and where x,y,z are all unique. Also by first I mean that if you take x>y and then order all solution (x,y,z) first by x, then by y, the first solution you will come across is the one for this problem.
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Posted by Daniel
on 2009-07-29 22:58:18 |
re(3): Integrity? (interesting property)
