Solve this alphametic, where each of the capital letters in bold denotes a different decimal digit from 0 to 9. None of the numbers can contain any leading zero.
^{3}√(HOW)+ ^{3}√(AND) = ^{3}√(WHEN)
(In reply to
re(2): Integrity? (interesting property) by ed bottemiller)
yes I fully understand that x^(1/3)+y^(1/3)=z^(1/3) is a simplification of the given problem. I was simply pointing out that the solution to the given problem is also the first nontrivial solution to x^(1/3)+y^(1/3)=z^(1/3) where by nontrivial I mean that neither x,y,z are perfect cubes (thus not breaking down to a simple addition of integers) and where x,y,z are all unique. Also by first I mean that if you take x>y and then order all solution (x,y,z) first by x, then by y, the first solution you will come across is the one for this problem.

Posted by Daniel
on 20090729 22:58:18 