Two smaller circles of radii a and b are internally tangent to a larger circle, of radius r, at points P and Q respectively. The smaller circles intersect at points S and T.
If P, S, and Q are collinear, prove that r = a+b.
(In reply to proof
Don't you also have to show that BS is parallel to PAR before you can say that ASBR is a parallelogram?
Clearly, the argument is similar to showing AS is parallel to QBR.
Posted by Bractals
on 2009-07-14 01:16:25