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Quadrilateral in a rectangle (Posted on 2009-07-17) Difficulty: 2 of 5
Given a rectangle with diagonal length d. On each side pick an arbitrary point that is not a corner.
Let u, x, y, and z be the side lengths of the convex quadrilateral determined by these four points.

Prove that
   d2 ≤ u2 + x2 + y2 + z2 < 2d2.

See The Solution Submitted by Bractals    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Solution - your reason to edit | Comment 3 of 5 |
(In reply to re: Solution - your reason to edit by brianjn)

No, I typed it in on-line. It's always worked before.

One of life's many mysteries..

Thanks for your concern anyway.

  Posted by Harry on 2009-07-18 16:53:08
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