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Quadrilateral in a rectangle (Posted on 2009-07-17) Difficulty: 2 of 5
Given a rectangle with diagonal length d. On each side pick an arbitrary point that is not a corner.
Let u, x, y, and z be the side lengths of the convex quadrilateral determined by these four points.

Prove that
   d2 ≤ u2 + x2 + y2 + z2 < 2d2.

See The Solution Submitted by Bractals    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(4): Solution - your reason to edit Comment 5 of 5 |
(In reply to re(3): Solution - your reason to edit by Charlie)

On the other hand, I could check "view source" and put int the html code for a capital sigma:


and, well, it still didn't work.

Edited on July 19, 2009, 1:08 pm
  Posted by Charlie on 2009-07-19 13:08:13

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