All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Pan Shared (Posted on 2009-07-22) Difficulty: 2 of 5

No Solution Yet Submitted by brianjn    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts Just some consideration! | Comment 1 of 2

Hi!

I try to find the integer factorization for all this numbers.

So i found :

1-1
12-2^2x3^1
123-3^1x41^1
1234-2^1x617^1
12345-3^1x5^1x823^1
123456-2^6x3^1x643^1
1234567-127^1x9721^1
12345678-2^1x3^2x47^1x14593^1
123456789-3^2x3607^1x3803^1

1-1
21-3^1x7^1
321-3^1x107^1
4321-29^1x149^1
54321-3^1x19^1x953^1
654321-3^1x218107^1
7654321-19^1x402859^1
87654321-3^2x1997^1x4877^1
987654321-3^2x17^2x379721^1

After this i read about powerfull numbers here

http://en.wikipedia.org/wiki/Powerful_number

So from all this numbers, only 1 is a powerfull number because in the integer factorization af all others number there is at least one factor with exponent 1.

And from all this number, only 1 is a perfect square!

So I belive, the wanted number is 1.

 


  Posted by Chesca Ciprian on 2009-08-16 14:53:37
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information