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x + y *
^{3}
√2 + z *
^{3}
√4 = 0 (
Posted on 20091015
)
Each of x, y and z is a rational number such that: x + y *
^{3}
√2 + z *
^{3}
√4 = 0.
Prove that x=y=z=0 is the only possible solution to the above equation.
No Solution Yet
Submitted by
K Sengupta
Rating:
3.0000
(1 votes)
Comments: (
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)
re: Nonrigorous argument
 Comment 2 of 14 
(In reply to
Nonrigorous argument
by Jim Keneipp)
I disagree with #3.
2sqrt(2) + sqrt(2) = 2
Posted by
Jer
on 20091015 14:59:19
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