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x + y * 3√2 + z * 3√4 = 0 (Posted on 2009-10-15) Difficulty: 3 of 5
Each of x, y and z is a rational number such that: x + y * 3√2 + z * 3√4 = 0.

Prove that x=y=z=0 is the only possible solution to the above equation.

No Solution Yet Submitted by K Sengupta    
Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Non-rigorous argument | Comment 2 of 14 |
(In reply to Non-rigorous argument by Jim Keneipp)

I disagree with #3. 

2-sqrt(2) + sqrt(2) = 2

  Posted by Jer on 2009-10-15 14:59:19

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