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x + y *
^{3}
√2 + z *
^{3}
√4 = 0 (
Posted on 20091015
)
Each of x, y and z is a rational number such that: x + y *
^{3}
√2 + z *
^{3}
√4 = 0.
Prove that x=y=z=0 is the only possible solution to the above equation.
No Solution Yet
Submitted by
K Sengupta
Rating:
3.0000
(1 votes)
Comments: (
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re(4): Solution  Extra font facility
 Comment 7 of 14 
(In reply to
re(3): Solution  Extra font facility
by Charlie)
So even that doesn't work.
Posted by
Charlie
on 20091015 22:44:44
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