Consider a hollow sphere of radius R, in which a light source is placed at its centre. A square plate of side length S is held in place within the sphere by a pole of length L units. The square plate's position is then such that the displacement between the centre of the square and the light source is R-L units.
The square plate is also oriented in a way such that an imaginary line drawn perpendicular to the surface of the plate and passing through the plate's centre will pass through the light source.
Determine the surface area of the shadow formed on the spherical shell, due to the square plate.
The solution I came up with is:
Calculating the dihedral angle of planes that make the lateral faces of the pyramid with the base representing the square plate and the apex being the center of the sphere we find the angles of the shadow on the sphere.
H=R-L -height of pyramid
√2)/2 -semi-diagonal of the square plate.
HL= √(S²/4+(L-R)²) -lateral height of the pyramid
E= √(S²/2+(L-R)²) -lateral edge of the pyramid
AL= (S*HL)/2 -area of one lateral face of the pyramid
HS2= S*HL/E -distance from one corner of the base to the lateral edge of the pyramid(this point being the place where we calculate the dihedral angle, as the line from this point (we name it X) and the corner of the base is perpendicular to the edge of the pyramid which represents the intersections of the planes that are limiting the shadow on the sphere.
H2- line from X to the center of the square plate
β= arcsin(D/HS2) -angle formed by H2 and HS2 which is half of the dihedral angle we are looking for.
( √2 √[S²/2+(L-R)²] )
β=arcsin( ---- * -------------------- )
( 2 √[S²/4+(L-R)²] )
Now, using β we can calculate the area of a spherical triangle that is half the area of the shadow, using formula:
Area = R²[(A+B+C)-π] -A, B, C being angles of the spherical triangle, in our case A=B=β and C=2β
<img src="http://img183.imageshack.us/img183/3193/formulaw.jpg" alt="Formula"><img src="http://img183.imageshack.us/img183/1671/drawingm.th.png" border="0">