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| Sum (Pair Product) = Sum (Triplet Product) (Posted on 2009-11-08) |
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Determine the probability that for a positive integer N chosen at random between 1000 and 9999 inclusively, the sum of the products of pairs of digits in N is equal to the sum of products of triplets of its digits.
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Submitted by K Sengupta
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Rating: 4.0000 (1 votes)
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Solution:
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(Hide)
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The required probability is 51/9000 = 17/3000 = 0.5667 0.00566 (approx.)
For a detailed explanation, refer to the solution submitted Dej Mar in this location.
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