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 Sum (Pair Product) = Sum (Triplet Product) (Posted on 2009-11-08)
Determine the probability that for a positive integer N chosen at random between 1000 and 9999 inclusively, the sum of the products of pairs of digits in N is equal to the sum of products of triplets of its digits.

 Submitted by K Sengupta Rating: 4.0000 (1 votes) Solution: (Hide) The required probability is 51/9000 = 17/3000 = 0.5667 0.00566 (approx.) For a detailed explanation, refer to the solution submitted Dej Mar in this location.

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 Subject Author Date solution Dej Mar 2009-11-08 21:03:18 computer solution Charlie 2009-11-08 16:42:29 questions? Daniel 2009-11-08 14:51:02
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