ABCDE * 4 = EDCBA. Solve for A,B,C,D, and E where each is a unique integer that can take any value from 0 to 9.

A has to be 0, 1, or 2, due to the sum can't be more than 5 digits. A thus can't be 1 either because nothing 0-9 x 4= a number with 1 as a one's digit. Also, A cannot be 0 because 0x4=0 and 0 can't be E. thus A=2

E then must be 8.

also just as a heads up,

13333A + 1330B + 100C - 320D - 3332E = 0

13333A + 1330B + 100C = 320D + 3332E

26666 + 1330B + 100C = 320D + 26656

1330B + 100C + 10= 320D

133B + 10C + 1 = 32D

According to this, B must be odd, so it's probably 1.

Edited on November 9, 2003, 8:57 am

Edited on November 9, 2003, 8:58 am

Edited on November 9, 2003, 9:01 am

Edited on November 9, 2003, 9:09 am

Edited on November 9, 2003, 9:12 am

Edited on November 9, 2003, 9:14 am

Edited on November 9, 2003, 9:15 am
Edited on November 9, 2003, 9:18 am

Posted by Victor Zapana on 2003-11-09 08:53:55