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This Way and That Way (Posted on 2003-11-09) Difficulty: 3 of 5
ABCDE * 4 = EDCBA. Solve for A,B,C,D, and E where each is a unique integer that can take any value from 0 to 9.

See The Solution Submitted by Ravi Raja    
Rating: 3.4000 (5 votes)

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I need some digitalis !!!! | Comment 4 of 12 |
(Since the integers must be unique, we can discount the obvious trivial solution, A=B=C=D=E=0)

In the base 10 number system:

(E +10D +100C +1000B+ 10000A) *4 = A + 10B + 100C + 1000D + 10000E

39999A + 3990B + 300C - 960D - 9996E = 0

Now all I need is a handy dandy computer program or spreadsheet to give me the 0-to-many unique solutions.

Edited on November 9, 2003, 1:04 pm
  Posted by Dan on 2003-11-09 13:02:28
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