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Double Coverage (Posted on 2009-09-29) Difficulty: 2 of 5
The two pentominos pictured below cannot tile any rectangle.
+--+  +--+   +--+--+
|  |  |  |   |  |  |
+--+--+--+   +--+--+--+--+
|  |  |  |      |  |  |  | 
+--+--+--+      +--+--+--+
Take eight copies of one pentomino and place them on a 4x5 rectangle such that each 1x1 subsquare of the rectangle has exactly two pentominos covering it.

No Solution Yet Submitted by Brian Smith    
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re: considering second pentomino | Comment 3 of 4 |
(In reply to considering second pentomino by Charlie)

As far as I can tell your program does not allow for reflections of the polyomino.


  Posted by Brian Smith on 2009-09-30 00:45:40
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