Given a set of 9 points, no 3 collinear
, prove there must be a subset of 5 that forms a convex pentagon.
(In reply to re(2): Happy Ending
"Just don't ask us to prove N(6)=17...."
I didn't even try to find a 16 point configuration with no convex hexagon!
Posted by Jer
on 2009-10-19 01:48:22