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9 points to convex pentagon (Posted on 2009-10-12)

Given a set of 9 points, no 3 collinear, prove there must be a subset of 5 that forms a convex pentagon.

No Solution Yet Submitted by Jer

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re(3): Happy Ending

Comment 4 of 4 |

(In reply to re(2): Happy Ending by Harry)

"Just don't ask us to prove N(6)=17...."

I didn't even try to find a 16 point configuration with no convex hexagon!

Posted by Jer on 2009-10-19 01:48:22

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