Determine all possible values of a 6-digit positive integer N having 6 different digits from 0 to 9, with the first digit being nonzero, such that:
(i) Either, the digits at the even positions are even and the digits at the odd positions are odd – or, the digits at the even positions are odd and the digits at the odd positions are even. Zero is regarded as an even digit.
(ii) The absolute difference between two adjacent digits is always greater than one.
(iii) The 2-digit number formed by the first and second digit as well as the 2-digit number formed by the third and fourth digit is divisible by the 2-digit number formed by the fifth and sixth digit.
in no time:
MN = TWO DIFF. DIGITS OUT OF 2,4,5,7
ALL TOGETHER 12 POSSIBILITIES
easy - logical trial
Edited on January 1, 2010, 12:37 pm